Replacing Values in a FrameΒΆ

This example shows how to replace numeric values in a frame of data. Note that it is currently not possible to replace categorical value in a column.

> library(h2o)
> df <- h2o.importFile(path)

# Replace a single numerical datum. Note that columns and rows start at 0, so in the example below, the value in the 15th row and 3rd column will be set to 2.0.
> df[14,2] <- 2.0

# Replace a whole column. The example below multiplies all values in the second column by 3.
> df[,1] <- 3*df[,1]

# Replace by row mask. The example below searches for value less than 4.4 in the sepal_len column and replaces those values with 4.6.
> df[df[,"sepal_len"] < 4.6, "sepal_len"] <- 4.6

# Replace using ifelse. Similar to the previous example, this replaces values less than 4.6 with 4.6.
> df[,"sepal_len"] <- h2o.ifelse(df[,"sepal_len"] < 4.4, 4.6, df[,"sepal_len"])

# replace missing values with 0
> df[is.na(df[,"sepal_len"]), "sepal_len"] <- 0

# alternative with ifelse
> df[,"sepal_len"] <- h2o.ifelse(is.na(df[,"sepal_len"]), 0, df[,"sepal_len"])

>>> import h2o
>>> h2o.init()
>>> df = h2o.import_file(path=path)

# Replace a single numerical datum. Note that columns and rows start at 0, so in the example below, the value in the 15th row and 3rd column will be set to 2.0.
>>> df[14,2] = 2.0

# Replace a whole column. The example below multiplies all values in the first column by 3.
>>> df[0] = 3*df[0]

# Replace by row mask. The example below searches for value less than 4.6 in the sepal_len column and replaces those values with 4.6.
>>> df[df["sepal_len"] < 4.6, "sepal_len"] = 4.6

# Replace using ifelse. Similar to the previous example, this replaces values less than 4.6 with 4.6.
>>> df["sepal_len"] = (df["sepal_len"] < 4.6).ifelse(4.6, df["sepal_len"])

# Replace missing values with 0.
>>> df[df["sepal_len"].isna(), "sepal_len"] = 0

# Alternative with ifelse. Note the parantheses.
>>> df["sepal_len"] = (df["sepal_len"].isna()).ifelse(0, df["sepal_len"])